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8v^2+v-21=0
a = 8; b = 1; c = -21;
Δ = b2-4ac
Δ = 12-4·8·(-21)
Δ = 673
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{673}}{2*8}=\frac{-1-\sqrt{673}}{16} $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{673}}{2*8}=\frac{-1+\sqrt{673}}{16} $
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